Question

15 men take 42 days of 4 hours each to do a piece of
work. How many days of 6 hours each would 21 women
take if 3 women do as much work as 2 men?​

Answer 1

Answer:

Number of Man- hours required to complete the work = (15 x 42 x 4) hours.

Number of days required by 21 women , to complete the work, working 6- hours a day = (15 x42 x 4) ÷ (21 x 2/3 x 6) =30days.

. [ Because 3women = 2 men ; 21women =21 x 2/3 = 14 men]