Question

15 moles of SO2 is made to react with 22.4L of H2S at STP. What will be the weight of Sulphur obtained?​

Answer 1

Answer:

Explanation:

we have, 11.2 L of SO  

2

​  

 = 0.5 mole

for 1 mole of SO  

2

​  

 we require 2 moles of H  

2

​  

S

and for 0.5 mole of SO  

2

​  

 we require 1 moles of H  

2

​  

S

so, we have SO  

2

​  

 as  a limiting reagent

1 mole of SO  

2

​  

 form 3 mole of sulphur

0.5 mole of SO  

2

​  

 produce S = 0.5 * 3 = 1.5 mole