15 omega,10 omega ,5 omega resistors are connected in parallel. what is the equivalent resistance of this connection?
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hey buddy !! here's your answer....
★ since the resistors are connected in parallel
1/R = 1/15 + 1/10 + 1/5
taking L.C.M
1/R = 2 + 3 + 6 / 30
1/R = 11/30
R = 30/11 ohm ✔️
hope it helps !! ❤️✌️
⭐⭐
★ since the resistors are connected in parallel
1/R = 1/15 + 1/10 + 1/5
taking L.C.M
1/R = 2 + 3 + 6 / 30
1/R = 11/30
R = 30/11 ohm ✔️
hope it helps !! ❤️✌️
⭐⭐
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