Question

15 points



Please answer with explanation.​

Answer 1

$question \\ if \: one \: of \: the \: quadratic \: polynomial \: \\ {x}^{2} + 3x + k \: is \: 2 \: then \: the \: \\ value \: of \: k \: is \: . \\ \\ solution. \\ \\ p(x) = {x}^{2} + 3x + k = 0\\ \\ p(2) = {2}^{2} + 3(2) + k = 0\\ \\ 4 + 6 + k = 0\\ \\ 10 + k = 0 \\ \\ k = - 10 \: \: \\ \\ option \: (b) = -10 \: is \: the \: correct \: answer...$

Answer 2

Answer:

Option (b)-10

Step-by-step explanation:

Given,

One of the root of the quadratic polynomial is 2

x²+3x+K is the quadratic equation

So p(x) = x²+3x+K

Lets substitute 2 in the place of 'x' as it is one of the root of the equation.

Making p(x) = p(2).

= p(2) = 2²+3*2+k

= 4+6+k  

=  10+k

10 + k = 0(transposing 10 to right side makes it -10)

k = -10

Here the value of K is -10.