Question

15) Prove that three times the sum of the squares of the sides of a triangle is equal to four times the
Sum of squares of the medians of that triangle
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Answer 1

Sol: Apollonius theorem states that the sum of the squares of two sides of a triangle is equal to twice the square of the median on the third side plus half the square of the third side. Hence AB2 + AC 2 = 2BD 2 + 2AD 2 = 2 × (½BC)2 + 2AD2 = ½ BC2 + 2AD2 ∴ 2AB2 + 2AC 2 = BC2 + 4AD2 → (1) Similarly, we get 2AB2 + 2BC2 = AC2 + 4BE2 → (2) 2BC2 + 2AC2 = AB2 + 4CF2 → (3) Adding (1) (2) and (3), we get 4AB2 + 4BC2 + 4AC 2 = AB2 + BC2 + AC2 + 4AD2 + 4BE2 + 4CF2 3(AB2 + BC2 + AC2) = 4(AD2 + BE2 + CF2) Hence, three times the sum of squares of the sides of a triangle is equal to four times the sum of squares of the medians of the triangle.