Question

15)Show that x 2 +6x+11 has no zeros .

Answer 1

x=2+6x+11
x-6x=11+2
-5x=13
-x=13÷5
x=-13÷5

Answer 2

x^2 + 6x + 11................ Comparing it with ax^2 + bx +c....................,.. a= 1... b= 6...... c= 11............ Now take out the discriminant......... D = b^2 - 4ac........... D= 6^2 - 4×1×11............. D= 36-44...... D= -8.......... Since the value of D is in negative form , this means that no real roots or zeros' exists for the following equation...,......... Hence proved...