Question

If x a = y, y b = z and z c = x then prove that abc= 1

Answer 1

I understood the question like this

$x^{a} = y, y^{b} = z, z^{c} = x$

Consider

[tex] x^{a} = y [/tex]
But 
$z^{c} = x$

$(z^{c})^a = y \Rightarrow z^{ca} = y$

[But $y^{b} = z$

$\Rightarrow (y^{b})^{ca} = y \Rightarrow y^{abc} = y$

Therefore, abc = 1

Answer 2

Answer:

Step-by-step explanation: