Question

15. The HCF of three numbers is 8. The sum of the other numbers is 80. List the possible sets of such three numbers.​

Answer 1

Answer:

(8,16,56), (8,24,48) or (8,32,40)

Step-by-step explanation:

HCF of three number is 8.

Let the numbers be 8x, 8y and 8z where x,y and z are co-prime.

Their sum is 80

→80 8x + 8y + 8z = 10

→ 8(x+y+z) = 80

→ x+y+z=10

The three co-prime numbers whose sum is 10 are: (1,2,7), (1,3,6) and (1,4,5).

Hence, the numbers can be (8,16,56), (8,24,48) or (8,32,40).

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Answer 2

HOPE IT HELPS YOU BUDDY :)