Question

15. The HCF of two numbers is 36 and their LCM is 1512. If one of the numbers is 216 find the other number.​

Answer 1

Solution

Let the required number be x

We know that,

HCF × LCM=product of the numbers

Implies,

→36×1512=216x

→x=36×1512/216

→x=1512/6

→x=252

Thus,the required number is 252

Answer 2

Step-by-step explanation:

Hi,

HCF of two numbers = 36

LCM of two numbers = 1512

One number = 216

Other number = ?

We know that ,

One number× Other number = HCF ×LCM

216 × Other number = 36 × 1512

Other number = 36*1512/216

Other number = 36 × 7

Other number = 252

Hope it will help you:)