Question

15. The range of a projectile when launched at angle theta is
same as when launched at angle 2 theta What is the value
of theta?​

Answer 1

Answer:

The value of theta is 30.

Explanation:

When an object moves as a projectile the maximum distance it covers is no is the range of projectile. $\mathrm{R}=\frac{V^{2} \sin \theta}{G}$ is the formula to determine the range.

here are given two angles one being the double of father but the range  of projectile is same applying this in the formula:-

$\mathrm{R}=\frac{V^{2} \sin \theta}{G}$

When the angle is double that is 2ө

$\mathrm{R}=\frac{v^{\mathrm{a}} \sin 2 \theta}{G}$

Equating both since range  

$\begin{array}{l}{\frac{V^{2} \sin 2 \theta}{G}=\frac{V^{2} \sin \theta}{G}} \\ {\frac{V^{2} 2 \sin \theta \cos \theta}{G}=\frac{V^{2} \sin \theta}{G}}\end{array}$

• 2sinӨ = 1
• sinӨ = ½
• Ө=30
• 2Ө =60