Question

15. The sum of 1.03 + (1.03 ) 2 + (1.03 ) 3 + .... to n terms is
(a) 103 {(1.03) - 1} (b) 103/3 {(1.03 )" – 1} (c) (1.03)n-1
(d) none of these

answer is: b) 103/3(1.03)*n-1)​

Answer 1

Answer:

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