Chemistry, asked by saksham73819, 7 months ago

15
The sum of first and second ionization energies and those of third and fourth ionization
energies in (kJ mol-') of nickel and platinum are
(IE), + (IE)2
(IE)3 + (IE)4
Ni 2.49
8.80
Pt 2.66
6.70
Based on this information; write
(i) the most common oxidation states of Ni and Pt.
(ii) Name of metal (Ni or Pt) which can more easily form compounds in its +4 oxidation
state.​

Answers

Answered by sanjeevmathur198083
1

For Ni, (IE)

1

+(IE)

2

<<(IE)

3

+(IE)

4

.

Thus, the difference is very large.

Hence, the stable oxidation of Ni is +2.

For Pt (IE)

1

+(IE)

2

<(IE)

3

+(IE)

4

.

Thus, the difference is small.

Hence, the stable oxidation of Ni is +4.

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