15-Three objects A, B and C are kept in a straight line on a frictionless horizontal surface.
These have masses m, 2m and m respectively. The object A moves towards B with a
speed 9m/s and makes an elastic collision with it. Thereafter, B makes completely
inelastic collision with C. All motions occur on the same straight line. The final speed of
the object C is
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Answer:
4 m/s
Explanation: For perfectly elastic and inelastic collision conserve momentum and energy.
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Given :
mass of A = m
mass of B = 2m
mass of c = m
velocity of A = 9 m/s
To find :
The final speed of C .
Solution :
let the velocity after the collision be va , vb , vc .
on conserving momentum for 1st collision , we get ,
va + 2 vb = 9 .....(i)
on conserving energy for the 1st collision , we get ,
va^2 + 2 vb^2 = 81 ......(ii)
by (i) and (ii) ,
vb = 6 m/s
The second collision is perfectly inelastic . So , after the collision the bodies will attain same velocity and move as one body .
on conserving momentum , we get ,
2m * vb = (2m + m) * vc
vc = (2/3) * vb
=> vc = 4 m/s
The final speed of the object C is 4 m/s .
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