Question

A ball is projected vertically upwards. Its speed at
half of maximum height is 30 m/s. Maximum height
attained by the ball is​

Answer 1

Answer:

0= U^2-2as

900=2×10×s

s=45

so 2×s= 90 metre may be the answer

I am giving my best

Answer 2

Answer:

H/2 = {u^2 × (sinx)^2}/2g

H/2 = {30 × 30 × 1}/2 × 10

H/2 = 900/2×10

H = 90m