15. Two dice are thrown together a.how may total pairs of numbers occur on both the dice b.Find the probability of the sum on both dice is 6 c. Find the probability of the same numbers on both dice d. Find the probability that the product is a prime number
Answers
Answer:
a) Two dice are thrown together
so total no. of outcomes =6×6=36
Favorable outcomes ={(1,6),(2,3),(3,2),(6,1)}
P (of getting a 6)=
36
4
=
9
1
b) Favorable are of getting the product on the top of the
dice =(2,6)(6,2)(4,3)(3,4)
Total favourable outcomes = 4
P (of getting the product of the no on the top of dice 12 )
=
Totalnoofoutcomes
Totalno.offavourablecases
=
36
4
=
9
1
c) Favorable cases of getting the product of no. on the top of dice 7=0
P (of getting the product of no. on the top of dice 7)
Totalno.ofoutcomes
Totalno.offavourablecases
=
36
0
=0
Answer:
No.of possible outcomes = 36
(a) Favourable outcomes = (1,1)(2,2)(3,3)(4,4)(5,5) and (6,6)
No. of favourable outcomes = 6
P( total pairs of numbers occur on both the dice)=6/36=1/6
(b) Favourable outcomes = (1,5)(2,4)(3,3)(4,2)(5,1)
No. of favourable outcomes = 5
P(the sum on both dice is 6)= 5/36
(c)Favourable outcomes = (1,1)(2,2)(3,3)(4,4)(5,5) and (6,6)
No. of favourable outcomes = 6
P(the same numbers on both the dice) = 6/36 =1/6
(d) Favourable outcomes = (1,2)(1,3)(1,5)(2,1)(3,1)(5,1)
No. of favourable outcomes = 6
P(that the product is a prime number)= 6/36=1/6