Math, asked by rxx, 3 months ago

15. Two-third of a number added to 10 gives 20. Find the number.​

Answers

Answered by ishakumarisingh557
0

Let the number be x.

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)x

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5=>x=11*3

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5=>x=11*3=> x=33

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5=>x=11*3=> x=33Hence,the original number is 33.

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5=>x=11*3=> x=33Hence,the original number is 33.Rechecking through answer.

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5=>x=11*3=> x=33Hence,the original number is 33.Rechecking through answer.If 33 is the original number, Lets check if 22 is its 2/3rd.

Let the number be x.First part of the problem: a no. Added to the 2/3rd of its own.x + (2/3)xSecond part: is equal to 55x + (2/3)x = 55=> (5/3)x=55=> x= (55*3)/5=>x=11*3=> x=33Hence,the original number is 33.Rechecking through answer.If 33 is the original number, Lets check if 22 is its 2/3rd.33*(2/3)=>11*2=>22

Similar questions