Question

15. What smallest number must be multiplied in the denominator, so that the decimal 14588 number will be terminated? 625 (a) 4 (b) 18 (c) 16 (d) 20​

Answer 1

option A is correct i.e 4

Answer 2

Answer:

4

Step-by-step explanation:

The denomianator of a ternimanting decimal expansion should be

$\frac{1}{ {2}^{m}\times {5}^{n} }$

Where m and n are non negative integers

So by options

Case I

$\frac{14588}{2^{2} \times {5}^{0}}$

Case II

$\frac{14588}{ {2}^{1} \times{3}^{2} }$

Here its not in the form so it cant be the option

Case III and IV

The other two options are also in this form but the smallest number in this option is 4

So (a) is the answer

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