Question

15(y-4)-2(y-9)+5(y+6)=0​

Answer 1

Step-by-step explanation:

15(y-4)-2(y-9)+5(y+6)=0

= 15y - 60 - 2y+18 +5y +30 =0

=> 15y - 2y +5y - 60 +18 +30 =0

=> 18y - 12 = 0

=> 18y = 12

=> y = 12/18

=> y= 2/3

Answer 2

Given,

$\sf 15(y-4)-2(y-9)+5(y+6)=0$

We have to evaluate the value of y.

$\implies\sf 15(y-4)-2(y-9)+5(y+6)=0$

$\implies\sf [15y-(15\times4)]-[2y+(2\times-9)]+[5y+(5\times6)]=0$

$\implies\sf [15y-60]-[2y+(-18)]+[5y+30]=0$

$\implies\sf [15y-60]-[2y-18]+[5y+30]=0$

$\implies\sf 15y-60-2y+18+5y+30=0$

$\implies\sf 15y-2y+5y-60+18+30=0$

$\implies\sf 18y-12=0$

$\implies\sf 18y=12$

$\implies\sf y=\dfrac{12}{18}$

$\bold{\implies\sf y=\dfrac{2}{3}}$

Therefore,

$\huge\boxed{\bf Value\:of\:y=\dfrac{2}{3}}$