Math, asked by jotikumari20, 1 month ago

15 years ago, man was 5 times old as his son.if at present, he is twice as old as his sin, find the present age
step by step
please send answer I will mark you as brainlest​

Answers

Answered by sirireddykristipati
1

Answer:

present ages of Man is 40

Sun is 20

Step-by-step explanation:

15 years ago

(M - 15) = 5(S - 15)

M = 5S - 75 + 15

M = 5S - 60

present

M = 2S

5S - 60 = 2S

3S = 60

S = 20

M = 40

Answered by rishabh994
1

Step-by-step explanation:

Let's suppose that son's age = x year

Then father's age = 5x year

According to the question

15 years ago,

Age of son = x - 15

Age of Father = 5(x - 15) = 5x - 75

5x - 75 = 2 ( x - 15 )

5x = 2x - 30 + 75

5x - 2x = 45

3x = 45

x = 15

Present age of son = 15 years

And father's age = 5x = 5*15 = 75 years

Hope it helps you

Thank you

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