Question

150 ml, 2 M sulphuric acid solution is mixed with 350
ml, 1 M sulphuric acid solution. The resulting molarity
of the sulphuric acid solution is​

Answer 1

Answer:

0.67

Explanation:

As formula of dilution is

M1*V1=M2*V2.

HERE

M1=2MOLAR

V1=150ml

M2=?

V2=VOLUME OF WATER, THAT IS 350ml+VOLUME OF SULPHURIC ACID THAT IS 150 ml.

So,V2=350+150=500ml

Now from formula

SINCE M1V1=M2V2,

=> 2*150=M2*500

SO, M2=300/500=0.6MOLAR.

√\_________Anushka❤❤