150 students in a tenth grade high school class take a survey about which video game consoles they own. 60 students answer that one of their consoles is a Playstation, 50 answer that one of their consoles is an Xbox. Out of these, there are 20 who have both systems.
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Given:
Total Number of students surveyed = 150
Number of students having Playstation = 60
Number of students having XBox = 50
Number of students having both = 20
To Find:
The number of students having non of the console.
Solution:
Let A represent the event that a student has a playstation.
Let B represent the event that a student has a Xbox.
- Event that a student has both = A∩B
- Event that a student has either = n(A∪B)
- Even that a student has neither = Total students - n(A∪B)
Given,
- n(A) = 60
- n(B) = 50
- n(A∩B) =20
- n(A∪B) = n(A) + n(B) - n(A∩B)
- n(A∪B) = 60 + 50 - 20 = 90
Therefore the number of students having neither = 150 - 90 = 60
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