French, asked by Anonymous, 7 months ago

150 workers were engaged to finish a job in a Certain number of days. 4 workers dropped number of day, 4 more workers drop on third day so on. It took 8 more days to finish the work find the number pf days in which the work was completed. Please help me ​ ​jj

Answers

Answered by Anonymous
1

 \sf  \large \:\underline{ \red{Question }}:-

150 workers were engaged to finish a job in a Certain number of days. 4 workers dropped number of day, 4 more workers drop on third day so on. It took 8 more days to finish the work find the number pf days in which the work was completed.

 \sf  \large \:\underline{ \red{Given} }:-

150 workers were engaged to finish a job in a Certain number of days.

4 workers dropped number of day.

4 more workers drop on third day so on.

 \sf  \large \:\underline{ \red{To \: Find }}:-

Find the number pf days in which the work was completed.

 \sf  \large \:\underline{ \red{Solution }}:-

 \boxed{ \sf \: sum \: of \: n \: terms \:  =  \frac{n}{2} ( \:2a + (n - 1) \times d) }

∴ Total number of workers who would have worked all n days = 150 (n – 8)

 \sf \to \: n (152  -  2n) = 150 (n  - 8) \\  \\ </p><p></p><p>  \sf \to \: 152n  - 2n^2 = 150n  -  1200 \\ \\  \sf  \to \: 2n^2  -  2n  - 1200 = 0 \\  \\ </p><p></p><p> \sf \to \: n^2  - n  -  600 = 0 \\  \\ </p><p></p><p> \sf \to \: n^2 - 25n + 24n  -  600 = 0 \\  \\ </p><p></p><p> \sf  \to n(n  -  25) + 24 (n + 25) = 0 \\  \\ </p><p></p><p> \sf \to \:  (n  - 25) (n + 24) = 0 \\  \\ </p><p></p><p>  \sf \to \: n  - 25 = 0  \: or  \: n + 24 = 0 \\   \\ \sf \to \orange{ n = 25  \: or  \: n =   \: - 24}\: \huge \dag\\ </p><p></p><p>

 \sf \underline{ \red{n = 25  } \:  (Number  \: of  \: days \:  cannot  \: be \:  negative)}

 \text{ \green{ \underline{{Thus, the work is completed in 25 days.}}}}

Answered by Anonymous
2

Answer:

==》Let x be the number of days in which 150 workers finish the work.

According to the given information,

150x=150+146+142+...(x+8)terms

The series 150+146+142+...+(x+8) terms is an A.P. with first term 150, common difference -4 and number of terms as (x+8)

The series 150+146+142+...+(x+8) terms is an A.P. with first term 150, common difference -4 and number of terms as (x+8)

==》after this copy the attachment

Since, x cannot be negative . So, x=17

So, the number of days in which the work was to be completed by 150 workers is 17.

So, required number of days =(17+8)=25

Hope it helps u: )

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