Question

150ml 2M sulphuric acid mixed with 350ml of water the final molarity of the solution is​

Answer 1

Answer: Thus molarity of the solution will be 0.67 M.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n= moles of solute

$V_s$ = volume of solution in ml  

moles of $H_2SO_4=Molarity\times {\text {Volume in L}}=2M\times 0.15=0.3moles$

$Molarity=\frac{0.3\times 1000}{450}$

$Molarity=0.67M$

Thus molarity of the solution will be 0.67 M.

Answer 2

Answer:

Explanation:

As formula of dilution is

M1*V1=M2*V2.

HERE

M1=2MOLAR

V1=150ml

M2=?

V2=VOLUME OF WATER, THAT IS 350ml+VOLUME OF SULPHURIC ACID THAT IS 150 ml.

So,V2=350+150=500ml

Now from formula

SINCE M1V1=M2V2,

=> 2*150=M2*500

SO, M2=300/500=0.6MOLAR.

HOPE IT HELPSS!!!!

THNX..