Question

154. A bus is moving with a constant velocity v, along
a horizontal road. A man standing inside the bus
throws a ball upward with velocity V, and catches
the ball. The magnitude of displacement of the ball
with respect to ground is​

Answer 1

Answer:

2g metres =2*10 metres =20 metres

Explanation:

The ball when thrown is pulled by gravity and decelerates till it stops in air and the falls back to the man's hand. Let the time for ball to go up be t, then the total time for this process will be 2t.

Using first equation of Newtonian Motion,

$v=u+at$

Here,

v=0 m/s

u=V m/s

a= -g (As gravity is opposite to motion)

Solving, we get:

t=g/V sec

2t=2g/V sec

During this time, the total displacement of ball will be in the direction in which train moves. This can be calculated as

Distance=Speed*Time

=V*2g/V metres

=2g metres

Answer 2

Answer:

refers to attachment

Explanation:

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