Question

157
Straight Lines
7. If the line x-3y + 5 + k(x + y -3) = 0, where k is arbitrary, is
perpendicular to the line x + y = 1 then find k and the equation of the
first line.​

Answer 1

Answer:

-4/3

Explanation:

x-3y+5+k (x+y-3)=0

k (x+y-3)+x-3y=-5

k (1-3)+x-y=-5/-3

-2k=5/3-1 (now take LCM)

-2k=5+3/3

k=8/3×-2

k=-4/3