Question

15a(2p-3q)-10b(2p-3q) factorise the following polynomials (pls its urgent)​

Answer 1

Answer:

15a(2p-3q)-10b(2p-3q)

= (2p-3q) ( 15 a - 10 b )

= (2p-3q) * 5 ( 3a - 2b )

= 5(2p-3q) ( 3a - 2b ) ( answer )

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Answer 2

Step by step solution :

➦ (15a • (2p - 3q)) - 10b • (2p - 3q)

➦ [15a • (2p - 3q) - 10b • (2p - 3q)]

   Pull out     2p-3q 

After pulling out, we are left with : 

      (2p-3q) • ( 15a  *  1 +( 10b  *  (-1) 

Pulling out like terms :

  Pull out like factors .

   15a - 10b  =   5 • (3a - 2b) 

➢Final result : 5 • (2p - 3q) • (3a - 2b)