Question

15cotA=8
Find sinA and secA

Answer 1

15 cotA =8

cotA = 8/15

cot A = b/p

=> base = 8

and perpendicular= 15

using Pythagoras theorem

AC = 17 units

to find:

sinA = p/h = 15/17

sinA = 15/17

secA = h/b = 17/8

secA = 17/8

hope it will help you......

Answer 2

$\mathfrak{Answer:-}$

15cotA = 8

cotA = $\frac{8}{15}$

Opposite - 15

Adjacent - 8

Hyp. - √8²+15² = 17

sinA = $\frac{15}{17}$

secA = $\frac{17}{8}$