Question

15g of ethane at 380 torr and 273°c occupy a volume of

Answer 1

Answer:

According to pv=nrt

(380/760)*V=(15/30)*0.0821*546

Solve for the V

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Answer 2

Answer:

15g of ethane at 380 torrs and 273°c occupy a volume of 0.0589 L.

Explanation:

What is an ideal gas?

A gas which obeys all the gas laws, i.e., Boyle's Law, Charle's Law, and Avogadro's law, at all conditions of temperature and pressure is known as an ideal gas. This is a hypothetical concept, i.e., in normal conditions, such gases do not exist. All gases are 'real'.

Mathematically, it can be written as:

PV=nRT, where,

• P= Pressure
• V= Volume of the gas
• n= number of moles
• R= universal gas constant
• T= temperature

Calculation:

Given that,

Pressure= 380 torr = 380 mm Hg

Temperature= 273°C = (273 + 273)K = 546K

Weight of the ethane gas= 15 gm
The molecular weight of ethane= 30 gm
∴ The number of moles of ethane gas (n):

$n= \frac{15}{30} = \frac{1}{2} = 0.5$

R= 0.082 Latm/mol/K

Volume = x (let)

∴ By the problem,

$PV = nRT \\\Rightarrow 380 \times x = 0.5 \times 0.082 \times 546 \\\Rightarrow x = \frac{0.5 \times 0.082 \times 546}{380} \\\Rightarrow x = 0.0589$

Conclusion:

The volume of the gas sample supplied under the given conditions would be 0.0589 L.

You can learn more about the ideal gas equation by referring to the links below:

Write the ideal gas equation and mention the terms
https://brainly.in/question/13732672

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