Question

15t2 = 41t- 14 find the quardratic equation

Answer 1

x=7/3. x=2/5

Step-by-step explanation:

replace t by x

$15 {x}^{2} - 41x + 14 = 0 \\ 15 {x}^{2} - 35x - 6x + 14 = 0 \\ 5x(3x - 7) - 2( 3x - 7) = 0 \\ \\ 3x - 7 = 0 \: \: \: \: or \: \: \: 5x - 2 = 0 \\ x = \frac{7}{3} \: \: \: \:or \: \: \: \: x = \frac{2}{5}$

hope it helps u