Question

15th term of A.P7,13,19....is?

Answer 1

Answer:

95

Step-by-step explanation:

Tn =a +(n-1)d

T15 =7 +(15-1)6

        7+14*6

         7+88

          95

Where a is the 1st term and n is the number of terms and d is the common difference.

Answer 2

Answer :

$\large{\star\:\:\boxed{\bf{a_{15}\:=\:91}}\:\:\star}$

Explanation :

Given :–

• 7 , 13 , 19 ,... are in A.P.
• where a = 7 and d = 6 .

To Find :–

• a₁₅ (15th term of this A.P.)

Formula Applied :–

• $\boxed{\star\:\:\bf{a_n\:=\:a\:+\:(n\:-\:1)d}\:\:\star}$

Solution :–

We have ,

• a = 7
• d = 6
• n = 15 .

Putting these values in the Formula :

$\rightarrow\sf{a_n\:=\:a\:+\:(n\:-\:1)d}$

$\rightarrow\sf{a_{15}\:=\:7\:+\:(15\:-\:1)(6)}$

$\rightarrow\sf{a_{15}\:=\:7\:+\:(14\:\times\:6)}$

$\rightarrow\sf{a_{15}\:=\:7\:+\:84}$

$\rightarrow\boxed{\bf{a_{15}\:=\:91}}$

∴ 15th Term of this A.P. is 91 .