Question

Please answer these questions, urgent, please do not spam please give answers step by step I will make u brainliest please answer ​

Answer 1

Answer:

1 = 2x2+4x-x-2

2=p3+p3q+q2p+q3

3=2/3x3-2/3xy2+yx2-y3

Step-by-step explanation:

1= we will first multiply the x+2 by (2x) that will be = 2xsquare +4x

then we will multiply it with -1 that will be = -x-2

so, the answer will be 2x2+4x-x-2

2 = in the second one we will first multiply (p+q) with p2 that will be = p3+p2q  

and then as we have done in the first sum we will multiply (p+q)with q2 thst will be q2p+q3  

so, the answer will be p3+p2q+q2p+p3

3=dont think that this sum is a complicated sum this is a easy sum firstly we will multiply (x2-y2)with 2/3x that will be 2/3x3-2/3xy2

than we will multiply y with x2-y2  that will be = yx2-y3

so, the answer is =2/3x3-2/3xy2+yx2-y3

HOPE YOU LIKE THE ANSWER. BRO I HAVE DONE  A LOT OF WORK FOR YOU

PLEASE MARK ME AS BRAINLIST

Answer 2

To find :

Product of given expression

(1) (2x-1)(x+2)

➝ ( 2x × x ) + ( 2x × 2 ) - ( 1 × x ) - ( 1 × 2 )

➝ 2x² + 4x - x - 2

➝ 2x² + 3x - 2

_______________________________________________

(2) ( p² + q²) (p+q)

➝ ( p² × p ) + ( p² × q ) + ( q² × p ) + (q² × q)

$\sf \implies \: \: {p}^{(2 + 1)} \: + \: {p}^{2} q \: + \: {q}^{2} p \: + \: \: {q}^{(2 + 1)} \\ \\ \sf \implies \: \: {p}^{3} \: + \: {p}^{2} q \: + \: {q}^{2} p \: + \: \: {q}^{3}$

_______________________________________________

$\sf \bold{(3)} \: \: \bigg( \: \dfrac{2}{3} x \: + \: y \bigg)( {x}^{2} - {y}^{2} )$

$\sf \implies \: \: \bigg( \dfrac{2}{3} x \: \times \: {x}^{2} \bigg) + \bigg( \dfrac{2}{3} x \: \times \: {y}^{2} \bigg) \: + \: \bigg( \: y \times {x}^{2} \bigg) \: + \: \bigg( \: y \times {y}^{2} \bigg) \:$

$\sf \implies \: \: \bigg( \dfrac{2}{3} {x}^{(1 + 2)} \bigg) + \bigg( \dfrac{2}{3} x{y}^{2} \bigg) \: + \: \bigg( \: y {x}^{2} \bigg) \: + \: \bigg( \: {y}^{(1 + 2)} \bigg) \:$

$\sf \implies \: \: \dfrac{2}{3} {x}^{3} \: + \: \dfrac{2}{3} x{y}^{2} \: + \: \: y {x}^{2} \: + \: \: {y}^{3}$

_______________________________________________