Question

A net force of magnitude 0.6N acts on a body of mass 40g, initially at rest.
Calculate the magnitude of the resulting acceleration.

Answer 1

GiveN :

• Magnitude of force (F) = 0.6 N
• Mass of body (m) = 40g = 0.04 kg
• Initial velocity (u) = 0 m/s

To FinD :

• Magnitude of acceleration

SolutioN :

Use formula to calculate force :

$\dashrightarrow {\boxed{\tt{F \: = \: ma}}} \\ \\ \dashrightarrow \tt{a \: = \: \dfrac{F}{m}} \\ \\ \dashrightarrow \tt{a \: = \: \dfrac{0.6}{0.04}} \\ \\ \dashrightarrow \tt{a \: = \: \dfrac{60}{4}} \\ \\ \dashrightarrow \tt{a \: = \: 15} \\ \\ \underline{\sf{\therefore \: Magnitude \: of \: Acceleration \: is \: 15 \: ms^{-2}}}$

Answer 2

Solution :

✴ Given :-

• Magnitude of force = 0.6N
• Mass of body = 40g
• Initial velocity of body = zero

✴ To Find :-

• Magnitude of resultant acceleration produced by net force

✴ Concept :-

✏ This question is completely based on concept of 'Newton's second law of motion'.

Mathematically,

$\boxed{\sf{\pink{\large{F=ma}}}}$

• F denotes net force on body
• m denotes mass of body
• a denotes acceleration of body

✴ Conversation :-

▪ 1000 g = 1 kg

▪ 40 g = 0.04 kg

✴ Calculation :-

$\twoheadrightarrow\sf\:0.6=0.04\times a\\ \\ \twoheadrightarrow\sf\:a=\dfrac{0.6}{0.04}\\ \\ \twoheadrightarrow\:\boxed{\sf{\orange{\large{a=15\:ms^{-2}}}}}$

✴ Additional information :-

• Acceleration and Force are vector quantities.
• Vector quantity has both magnitude as well as direction.