Question

15th term of the AP x -7, x -2, X + 3, _ _ _ _ _ _ is​

Answer 1

a = x - 7

$d = a2 - a1 \\ d = x - 2 - (x - 7) \\ d = x - 2 - x + 7 \\ d = x - x - 2 + 7 \\ d = 5$

$a15 = a + 14d \\ a15 = (x - 7) + 14(5) \\ a15 = x - 7 + 70 \\ a15 = x + 63$

Answer 2

Answer:

a=x-7

d=(x-2)-(x-7)

d=x-2-x+7

d=5

t¹⁵=a+(n-1)×d

t¹⁵=x-7+(14×5)

t¹⁵=x-7+70

t¹⁵=x+63

15th term of AP =x+63