Question

15th term of the sequence x - 7, x - 2, x + 3,... is

Answer 1

Answer :

The Arithmetic sequence is

(x - 7), (x - 2), (x + 3), ...

The first term is

a1 = (x - 7)

and

the common difference is

d = (x - 2) - (x - 7)

= x - 2 - x + 7

= 5

So, the 15th term (n = 15) of the given Arithmetic sequence is

a15

= a1 + (n - 1)d

= (x - 7) + (15 - 1) × 5

= x - 7 + 14 × 5

= x - 7 + 70

= x + 63

#MarkAsBrainliest

Answer 2

Hi folka!!

Given :-
A.P. = (x - 7) , (x - 2) , (x + 3) ...

First Term [ a ] = x - 7

Common difference [ d ] = $a_2$ - $a_1$

= (x - 2) - (x - 7)

= x - 2 - x + 7

= 7 - 2

= 5

Now,
$15^{th}$ term of the A.P. :-

$a_{15}$ = a + (n - 1) × d

= (x - 7) + (15 - 1) × 5

= (x - 7) + 14 × 5

= x - 7 + 70

= x + 63

Hence!!
15th term of A.P. (Sequence) = x + 63

Hope it helps uuuu ^_~