Question

15x + 22y = 5

40x + 55y = 13

Solve for X and Y

( Elimination method)

Answer 1

$\huge{\bold{Hello!!!}}$



$\textbf{Elimination method}$

In this method, we eliminate one of the two variables to obtain an equation in one variable which can easily be solved. Putting the value of this variable in any one of the given equations, the value of the other variable can be obtained.

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Refer to the attachment above for your solution

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$\underline{\bold{Verification}}$

15x + 22y = 5 --------( 1 )

40x + 55y = 13--------( 2 )

Eq'n ( 1 )

LHS = 15 ( 1 / 5 ) + 22 ( 1 / 11 )

=> 3 + 2 = 5

= RHS

Eq'n ( 2 )

LHS = 40( 1 / 5 ) + 55 ( 1 / 11 )

=> 8 + 5 = 13

= RHS

$\boxed{LHS = RHS}$

$\textbf{Hence, it is verified}$

$\boxed{Thanks}$

$\textbf{Hope it helps!!!}$

Answer 2

Multiply eq 1 by 55 and eq 2 by 22
825x+1210y=275
880x+1210y=286
Subtract eq 4 from 3
-55x=-11
x=5
Substitute x=5 in eq 3
825(5)+1210y=275
4125+1210y=275
1210y=275-4125
y=3