A ball is thrown upwards from the surface of the moon with a velocity of 19.6 m/s. (a) How much time will it take to attain the maximum height? (b) How high will it go?
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u(initial velocity) = 19.6 m/s
at highest point v(final velocity)=0
using v=u+at
0=19.6 - 9.8 * t
t=19.6/9.8= 2s (time to reach max height)
now using v^2 - u^2 = 2as
0 - (19.6)^2 = 2* 9.8 * s
s= 19.6*19.6/2*9.8
s=19.6 m
at highest point v(final velocity)=0
using v=u+at
0=19.6 - 9.8 * t
t=19.6/9.8= 2s (time to reach max height)
now using v^2 - u^2 = 2as
0 - (19.6)^2 = 2* 9.8 * s
s= 19.6*19.6/2*9.8
s=19.6 m
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