15x +7y =29 and 9x +15y=39
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Sol:-
15x + 7y = 29 …… ( 1 )
9x + 15y = 39 …… ( 2 )
from eq 1
15x = 29 –7y
x = 29 – 7y /15 …… ( 3 )
now sub eq 3 in eq 2
then
9[29–7y/15] +15y = 39
261 – 63y + 225y = 585
162y = 324
y = 2
now sub y = 2 in eq 3
then
x = 29 –7(2)/ 15
x = 29 – 14 / 15
x = 15/15
x = 1
Hence the value of x = 1 & y = 2
Hope this will help u all
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