Question

15x²+27x+12 full factories for this question ​

Answer 1

Answer:

15x²+27x+12

=5x²+9x+4

=5x²+5x+4x+4

=(5x²+5x)+(4x+4)

=5x(x+1)+4(x+1)

=(x+1)(5x+4)

Answer 2

$\huge\rm\color{purple}{{\mathcal{A}}n{\mathcal{S}}w{\mathcal{E}}r:}$

${}$

$\bf{{\underline{To~factorise}}:}$

$\tt{~~~~~~~~15x^{2}+27x+12}$

$\color{navy}{\boxed{\sf S=27~,~~P=180~~~~(12~,~15)}}$

$\tt\longmapsto{(15x^{2}+15x)+(12x+12)}$

$\tt\longmapsto{[15x(x+1)~]+[12(x+1)~]}$

$\tt\longmapsto{(15x+12)(x+1)}$

$\bf\therefore{{\underline{The~factors~are}}:}$

$~~~~~~~~{ \color{purple}{ \underline{ \boxed{ \bf15x + 12}}}}\: \: \: \: { \sf{and}} \: \: \: \: { \color{purple}{ \underline{ \boxed{ \bf x + 1}}}}$