Question

15x² + x-6 find zero of the polynomial​

Answer 1

Answer:

The answer is minus 10 and plus 9(Zeroes of the polynomial given in the question)

Step-by-step explanation:

= 15$x^{2}$ + x - 6

Factorize using identity (x + a)(x + b) = $x^{2}$ + (a + b) + ab

So that we could get the factors

Multiply the first term's constant with last term

That is 15 X (-6) = -90

Now find the factors of -90 such that it add up to middle term

That is

1x(Middle term) = 10x + (-9)x

                         = 1x

10(a) X (-9)[b] = -90

Now factorize

= $x^{2}$ + (10 + (-9)x + 10 X (-9)

= $x^{2}$ + 10x - 9x + 10 X (-9)

Take common

= x(x + 10) - 9(x + 10)

Again take common

= (x - 9) (x + 10)[Factors of the polynomial 15$x^{2}$ + x - 6]

Zeroes of the polynomial 15$x^{2}$ + x - 6

x - 9 = 0 and x + 10 = 0

x = 9                 x = -10[According to factor theorem]