-16/1+i√3 into polar form
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Answer:
8 ( cos60° - i sin60° )
Step-by-step explanation:
16/1+i√3 = 16/1+i√3*(1-i√3)/(1-i√3)
= 16(1-i√3)/(1+3)
16/4 *((1-i√3) = 4(1-i√3)
2*4(1/2 - i√3/2)
8 ( cos60° - i sin60° )
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