Question

-16/1+i√3 into polar form

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Answer 1

Answer:

8 ( cos60° - i sin60° )

Step-by-step explanation:

16/1+i√3 = 16/1+i√3*(1-i√3)/(1-i√3)

= 16(1-i√3)/(1+3)

16/4 *((1-i√3) = 4(1-i√3)

2*4(1/2 - i√3/2)

8 ( cos60° - i sin60° )