Question

A ball is shot vertically upward with a given initial velocity. It reaches a maximum height of 100 m. If
on a second shot, the initial velocity is doubled then the ball will reach a maximum height of
(A) 70.7 m
(B) 141.4 m
(C) 200 m
(D) 400 m​

Answer 1

Answer:

D) 400m

At maximum height final velocity is zero and the acceleration is acceleration due to gravity.

Now, v^2-u^2=2as

here, v=0 and a=-g, taking g=10m/s^2,

s=(u^2)/(2g)

Hence maximum height is proportional to square of initial velocity. Hence,

h1/h2= (u1^2)/(u2^2)

h1=100m and u2=2u1

100/h2=1/4

h2=400m

Cheers!