Question

16(2p-3q)² —4(2p–3q)​

Answer 1

Factorization of the given expression

Answer:

On factorizing 16(2p-3q)² —4(2p–3q)​  we get 4(2p-3q) ( 8p - 12q - 1 )

Explanation:

Given expression is as follows

16(2p-3q)² —4(2p–3q)​

To factorize above expression first we need to take out common factors.

consider factors of both term

16(2p-3q)²  = 4 x 4 x (2p-3q) x ( 2p - 3q )

4(2p - 3q ) = 4 x (2p - 3q )

As we see 4 and (2p - 3q ) is common in both the terms , lets take out common factors

16(2p-3q)² —4(2p–3q)​

=> ( 4 x 4 x (2p-3q) x ( 2p - 3q )  ) - (4 x (2p - 3q ) )

=> 4 x (2p - 3q ) ( 4 x (2p - 3q )  - 1 )

=> 4(2p-3q) ( 8p - 12q - 1 )

Hence on factorizing 16(2p-3q)² —4(2p–3q)​  we get 4(2p-3q) ( 8p - 12q - 1 )