16(2p-3q)² —4(2p–3q)
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Factorization of the given expression
Answer:
On factorizing 16(2p-3q)² —4(2p–3q) we get 4(2p-3q) ( 8p - 12q - 1 )
Explanation:
Given expression is as follows
16(2p-3q)² —4(2p–3q)
To factorize above expression first we need to take out common factors.
consider factors of both term
16(2p-3q)² = 4 x 4 x (2p-3q) x ( 2p - 3q )
4(2p - 3q ) = 4 x (2p - 3q )
As we see 4 and (2p - 3q ) is common in both the terms , lets take out common factors
16(2p-3q)² —4(2p–3q)
=> ( 4 x 4 x (2p-3q) x ( 2p - 3q ) ) - (4 x (2p - 3q ) )
=> 4 x (2p - 3q ) ( 4 x (2p - 3q ) - 1 )
=> 4(2p-3q) ( 8p - 12q - 1 )
Hence on factorizing 16(2p-3q)² —4(2p–3q) we get 4(2p-3q) ( 8p - 12q - 1 )
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