Question

a 2.4 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 18 cm the distance of the object from the lens is 12 cm find the position size nature of the image formed using lens formula

Answer 1

h = 2.4 cm

f = 18 cm

u = -12 cm

According to lens formula ,

1/f = 1/v - 1/u

1/18 = 1/v - (- 1/ 12)

1/18 = 1/v + 1/12

1/v = 1/18 - 1/12

1/v = 2 - 3 /36

1/v = - 1 / 36

v = -36

m = v / u

= - 36 / - 12

= 3

Therefore , position of image = - 36 cm

Image is Virtual and Erect .

Size of image is magnified .

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