16.8 g of NaHCO3 when heated produces 9 g of Na2CO3 according to the following reaction: 2NaHCO3 Na2CO3 + H2O + CO2
i. Find the % purity of NaHCO3
ii. How much volume of CO2 will be produced at 1 atm and 27°C?
Answers
Answered by
7
Answer:
2NaHCO
3
Heat
Na
2
CO
3
+H
2
O+CO
2
↑
Explanation:
The molar mass of NaHCO
3
is 84 g/mol.
The molar masses of CO
2
and water are 44 g/mol and 18 g/mol respectively.
Thus, 2×84=168 g of NaHCO
3
on decomposition will loose 44+18=62 g.
Hence, 1.68 g of NaHCO
3
on decomposition will lose 0.62 g.
Hence, the weight of the residue will be 10−0.62=9.38 g.
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