Question

Obtain the expression for radius of circular path of charged particle in magnetic field

Answer 1

Explanation:

Assume that a charged particle ‘q’ is moving perpendicular to the uniform magnetic field B, i.e. θ = 90º. The perpendicular force F = qv x B acts as centripetal force, thus producing a uniform circular motion for the particle in a plane perpendicular to the field.

i.e., mv2 /r = qvB or mv/r = qB,

here m is the mass the particle, r is the radius of the circular path traced.

∴ r = mv/qB