16-9(a+b)² factorise the following
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Answered by
3
Answer:
16-9(a+b)^2
=(4)^2-{3(a+b)}^2
=(4)^2-(3a+3b)^2
={4+(3a+3b)}{4-(3a+3b)}
=(4+3a+3b)(4-3a-3b)
Answered by
2
Answer:
16-9(a+b)^2
16-9(a+b)(a+b)
16-9(a+b)(a+b) 16-9(a(a+b)+b(a+b))
16-9(a^2+an+b(a+b)
16-9a^2-18ab-9b^=-9a^-18ab-9b^+16
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