Question

16. A 70 kg man runs up a hill through a height of 3 meters in 2 seconds. His
average power output is (g =10 m/sec):​

Answer 1

Given:-

• Mass,m= 70kg

• Height ,h = 3m

• Time taken ,t = 2s

• Acceleration,a = 10m/s²

To Find:-

• Power ,P

Solution:-

Firstly we calculate the Work done.

• W = mgh

Substitute the value we get

→ W = 70×10×3

→ W = 700×3

→ W = 2100 J

Now , calculating the Power

• P = W/t

Substitute the value we get

→ P = 2100/2

→ P = 1050 Watt

Therefore, the power of the man is 1050 Watt.

Answer 2

Answer:

• The required power = 1050 Watts

Given:

• A 70 kg man runs up a hill through a height of 3 meters in 2 seconds.

• The given acceleration is 10m/s².

Need To Find:

• The required Power = ?

Solution:

✪ Iɴ ᴄᴀsᴇ 1:

• Find the Work done = ?

Formula used here:

• Work = mass × gravity × height

Putting the values:

➪ Work = 70 × 10 × 3

➪ Work = 70 × 30

➪ Work = 2100 Joule

Therefore:

• The work done is 2100 joules

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✪ Iɴ ᴄᴀsᴇ 2:

• Find the required power = ?

Formula used here:

• Power = Work/Time

Putting the values:

➜ Required power = 2100/2

➜ Required power = 1050 Watts

Therefore:

• The required power = 1050 Watts

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