Math, asked by narendrasingh121121, 11 months ago

16. A alloy of gold and silver weighs 30 grams in air and 28 grams in water. Assuming that under the weight of silver. And there is a decrease of + (of its weight) in the weight of gold, find the weight of both gold and silver in the alloy (A) 88 grams, 21 grams (B) 7. Gram, 22 grams (C) 8 grams, 21 grams (D) 22 grams, 0 grams

Answers

Answered by Anonymous

Answer:

Step-by-step explanation:

Hi✌️✌️

x = 8.8889 gm

y = 21.1111gm

Step-by-step explanation:

Let weight of silver in air be x and that of gold be y

Therefore, x + y = 30 ----> 1

Now in water,

Thus x - x/10 + y - y/19 = 28

=> (171x + 180y)/190 = 28

=> 171x + 180y = 5320 ---->2

Multiplying Eq. 1 by 180 we get

180x + 180y = 5400 ---->3

Subtrating Eq.2 from Eq.3

9x = 80

=> x = 8.8889 gm

Therefore y = 30 - x

=> y = 30 - 8.8889 = 21.1111gm

I hope it will help you ✌️✌️

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Answered by jonahfowlkes

Answer:

y = 30 - 8.8889 = 21.1111gm

Step-by-step explanation:

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