16. A ball P is dropped from the top of a tall tower and falls freely towards the earth.
Another ball Q is dropped from the top of the same tower exactly two seconds later.
Then the separation between P and Q two seconds after the dropping of the second ball
Q is (take g = 10 m/s2)
1) 10 m
2) 40 m
3) 60 m
4) 80 m
Answers
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Answer:
distance travelled by ball in time t is 21gt2
separation : s=21g42−21g32=5×16−5×7=35
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Given:
A ball P is dropped from the top of a tall tower and falls freely towards the earth.
Another ball Q is dropped from the top of the same tower exactly two seconds later.
To find:
Separation between P and Q after 2 seconds of dropping Q ball.
Calculation:
So , time for which P ball has fallen = 2+2 = 4 sec.
Let Displacement be d_(P):
Time for which ball Q falls is 2 secs.
Let displacement be d_(Q):
So , separation between P and Q :
So, separation is 60 m.
HOPE IT HELPS.
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