Question

16. A circular ring carries a charge Q, the variation of electric field with distance x measured from centre along axis
for x < <R can be given as R Radius of Ring​

Answer 1

Answer:

electric field along axis of circular ring is given by,

where, x is observation point along axis of circular ring and r is the radius of ring.

differentiating electric field with respect to x,

for maximum electric field,

r² = 2x²

or, x = ± r/√2

hence, there are two optimum points,

for getting which point value of x for maximum again differentiating with respect to x. and putting both the value.

you will get, at x = r/√2

so, maximum value of electric field at X = r/√2

so, = kq(r/√2)/(r²/2 + r²)^{3/2}

= kqr/{√2(r² + 2r²)^{3/2}/2√2}

= 2kqr/(3r²)^{3/2}

= 2kqr/(3√3r³)

= 2kq/3√3r²

Answer 2

Explanation:

this is the amswer

hope it helps